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(X+3)^2+5=(X+5)(X-5)+(4-X)
We move all terms to the left:
(X+3)^2+5-((X+5)(X-5)+(4-X))=0
We add all the numbers together, and all the variables
(X+3)^2-((X+5)(X-5)+(-1X+4))+5=0
We use the square of the difference formula
X^2+(X+3)^2+25+5=0
We add all the numbers together, and all the variables
X^2+(X+3)^2+30=0
We move all terms containing X to the left, all other terms to the right
X^2+(X+3)^2=-30
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